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Kimi Pārōnaki e ai ki x
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4x^{4-1}+2\times 4x^{2-1}
Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.
4x^{3}+2\times 4x^{2-1}
Tango 1 mai i 4.
4x^{3}+8x^{2-1}
Whakareatia 2 ki te 4.
4x^{3}+8x^{1}
Tango 1 mai i 2.
4x^{3}+8x
Mō tētahi kupu t, t^{1}=t.