Whakaoti i te x^4+3x^3-x-3x^3+x^2-5x+3

$$x ^ { 4 } + 3 x ^ { 3 } - x - 3 x ^ { 3 } + x ^ { 2 } - 5 x + 3$$

Aromātai

$$x^{4}+x^{2}-6x+3$$

Ngā Upane Otinga

Pahekotia te 3x^{3} me -3x^{3}, ka 0.

$$x^{4}-x+x^{2}-5x+3$$

Pahekotia te -x me -5x, ka -6x.

$$x^{4}-6x+x^{2}+3$$

Kimi Pārōnaki e ai ki x

$$2\left(2x^{3}+x-3\right)$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 3x^{3} me -3x^{3}, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{4}-x+x^{2}-5x+3)$$

Pahekotia te -x me -5x, ka -6x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{4}-6x+x^{2}+3)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$4x^{4-1}-6x^{1-1}+2x^{2-1}$$

Tango 1 mai i 4.

$$4x^{3}-6x^{1-1}+2x^{2-1}$$

Tango 1 mai i 1.

$$4x^{3}-6x^{0}+2x^{2-1}$$

Tango 1 mai i 2.

$$4x^{3}-6x^{0}+2x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$4x^{3}-6x^{0}+2x$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$4x^{3}-6+2x$$