Whakaoti i te x^3-3x+1x^5+4x^3+x^2+3x+1

$$x ^ { 3 } - 3 x + 1 x ^ { 5 } + 4 x ^ { 3 } + x ^ { 2 } + 3 x + 1$$

Aromātai

$$x^{5}+5x^{3}+x^{2}+1$$

Ngā Upane Otinga

Pahekotia te x^{3} me 4x^{3}, ka 5x^{3}.

$$5x^{3}-3x+1x^{5}+x^{2}+3x+1$$

Pahekotia te -3x me 3x, ka 0.

$$5x^{3}+1x^{5}+x^{2}+1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$5x^{3}+x^{5}+x^{2}+1$$

Kimi Pārōnaki e ai ki x

$$x\left(5x^{3}+15x+2\right)$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te x^{3} me 4x^{3}, ka 5x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(5x^{3}-3x+1x^{5}+x^{2}+3x+1)$$

Pahekotia te -3x me 3x, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(5x^{3}+1x^{5}+x^{2}+1)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 5x^{3-1}+5x^{5-1}+2x^{2-1}$$

Whakareatia 3 ki te 5.

$$15x^{3-1}+5x^{5-1}+2x^{2-1}$$

Tango 1 mai i 3.

$$15x^{2}+5x^{5-1}+2x^{2-1}$$

Tango 1 mai i 5.

$$15x^{2}+5x^{4}+2x^{2-1}$$

Tango 1 mai i 2.

$$15x^{2}+5x^{4}+2x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$15x^{2}+5x^{4}+2x$$