Whakaoti i te x^3-10x^2+23x-14+x+2

$$x ^ { 3 } - 10 x ^ { 2 } + 23 x - 14 + x + 2$$

Aromātai

$$x^{3}-10x^{2}+24x-12$$

Ngā Upane Otinga

Pahekotia te 23x me x, ka 24x.

$$x^{3}-10x^{2}+24x-14+2$$

Tāpirihia te -14 ki te 2, ka -12.

$$x^{3}-10x^{2}+24x-12$$

Kimi Pārōnaki e ai ki x

$$3x^{2}-20x+24$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 23x me x, ka 24x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-10x^{2}+24x-14+2)$$

Tāpirihia te -14 ki te 2, ka -12.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-10x^{2}+24x-12)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3x^{3-1}+2\left(-10\right)x^{2-1}+24x^{1-1}$$

Tango 1 mai i 3.

$$3x^{2}+2\left(-10\right)x^{2-1}+24x^{1-1}$$

Whakareatia 2 ki te -10.

$$3x^{2}-20x^{2-1}+24x^{1-1}$$

Tango 1 mai i 2.

$$3x^{2}-20x^{1}+24x^{1-1}$$

Tango 1 mai i 1.

$$3x^{2}-20x^{1}+24x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$3x^{2}-20x+24x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$3x^{2}-20x+24\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$3x^{2}-20x+24$$