Whakaoti i te x^2-x-380=0

$$x ^ { 2 } - x - 380 = 0$$

Whakaoti mō x

$$x=-19$$

$$x=20$$

Ngā Upane Whakamahi Tauwehe

Hei whakaoti i te whārite, whakatauwehea te x^{2}-x-380 mā te whakamahi i te tātai x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-1 ab=-380$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōraro te a+b, he nui ake te uara pū o te tau tōraro i tō te tōrunga. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -380.

$$1,-380 2,-190 4,-95 5,-76 10,-38 19,-20$$

Tātaihia te tapeke mō ia takirua.

$$1-380=-379 2-190=-188 4-95=-91 5-76=-71 10-38=-28 19-20=-1$$

Ko te otinga te takirua ka hoatu i te tapeke -1.

$$a=-20 b=19$$

Me tuhi anō te kīanga whakatauwehe \left(x+a\right)\left(x+b\right) mā ngā uara i tātaihia.

$$\left(x-20\right)\left(x+19\right)$$

Hei kimi otinga whārite, me whakaoti te x-20=0 me te x+19=0.

$$x=20 x=-19$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei x^{2}+ax+bx-380. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-1 ab=1\left(-380\right)=-380$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōraro te a+b, he nui ake te uara pū o te tau tōraro i tō te tōrunga. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -380.

$$1,-380 2,-190 4,-95 5,-76 10,-38 19,-20$$

Tātaihia te tapeke mō ia takirua.

$$1-380=-379 2-190=-188 4-95=-91 5-76=-71 10-38=-28 19-20=-1$$

Ko te otinga te takirua ka hoatu i te tapeke -1.

$$a=-20 b=19$$

Tuhia anō te x^{2}-x-380 hei \left(x^{2}-20x\right)+\left(19x-380\right).

$$\left(x^{2}-20x\right)+\left(19x-380\right)$$

Tauwehea te x i te tuatahi me te 19 i te rōpū tuarua.

$$x\left(x-20\right)+19\left(x-20\right)$$

Whakatauwehea atu te kīanga pātahi x-20 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-20\right)\left(x+19\right)$$

Hei kimi otinga whārite, me whakaoti te x-20=0 me te x+19=0.

$$x=20 x=-19$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x^{2}-x-380=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -1 mō b, me -380 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-1\right)±\sqrt{1-4\left(-380\right)}}{2}$$

Whakareatia -4 ki te -380.

$$x=\frac{-\left(-1\right)±\sqrt{1+1520}}{2}$$

Tāpiri 1 ki te 1520.

$$x=\frac{-\left(-1\right)±\sqrt{1521}}{2}$$

Tuhia te pūtakerua o te 1521.

$$x=\frac{-\left(-1\right)±39}{2}$$

Ko te tauaro o -1 ko 1.

$$x=\frac{1±39}{2}$$

Nā, me whakaoti te whārite x=\frac{1±39}{2} ina he tāpiri te ±. Tāpiri 1 ki te 39.

$$x=\frac{40}{2}$$

Whakawehe 40 ki te 2.

$$x=20$$

Nā, me whakaoti te whārite x=\frac{1±39}{2} ina he tango te ±. Tango 39 mai i 1.

$$x=-\frac{38}{2}$$

Whakawehe -38 ki te 2.

$$x=-19$$

Kua oti te whārite te whakatau.

$$x=20 x=-19$$

Ngā Upane mō te Whakaoti i te Pūrua

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$x^{2}-x-380=0$$

Me tāpiri 380 ki ngā taha e rua o te whārite.

$$x^{2}-x-380-\left(-380\right)=-\left(-380\right)$$

Mā te tango i te -380 i a ia ake anō ka toe ko te 0.

$$x^{2}-x=-\left(-380\right)$$

Tango -380 mai i 0.

$$x^{2}-x=380$$

Whakawehea te -1, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{1}{2}. Nā, tāpiria te pūrua o te -\frac{1}{2} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=380+\left(-\frac{1}{2}\right)^{2}$$

Pūruatia -\frac{1}{2} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-x+\frac{1}{4}=380+\frac{1}{4}$$

Tāpiri 380 ki te \frac{1}{4}.

$$x^{2}-x+\frac{1}{4}=\frac{1521}{4}$$

Tauwehea x^{2}-x+\frac{1}{4}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{2}\right)^{2}=\frac{1521}{4}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{1521}{4}}$$

Whakarūnātia.

$$x-\frac{1}{2}=\frac{39}{2} x-\frac{1}{2}=-\frac{39}{2}$$

Me tāpiri \frac{1}{2} ki ngā taha e rua o te whārite.

$$x=20 x=-19$$