Whakaoti i te x^2-b=frac{20sqrt{1}}{5}

$$x ^ { 2 } - b = \frac { 20 \sqrt { 1 } } { 5 }$$

Whakaoti mō b

$$b=x^{2}-4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 5.

$$5x^{2}-5b=20\sqrt{1}$$

Tātaitia te pūtakerua o 1 kia tae ki 1.

$$5x^{2}-5b=20\times 1$$

Whakareatia te 20 ki te 1, ka 20.

$$5x^{2}-5b=20$$

Tangohia te 5x^{2} mai i ngā taha e rua.

$$-5b=20-5x^{2}$$

Whakawehea ngā taha e rua ki te -5.

$$\frac{-5b}{-5}=\frac{20-5x^{2}}{-5}$$

Mā te whakawehe ki te -5 ka wetekia te whakareanga ki te -5.

$$b=\frac{20-5x^{2}}{-5}$$

Whakawehe -5x^{2}+20 ki te -5.

$$b=x^{2}-4$$

Whakaoti mō x (complex solution)

$$x=-\sqrt{b+4}$$

$$x=\sqrt{b+4}$$

Whakaoti mō x

$$x=\sqrt{b+4}$$

$$x=-\sqrt{b+4}\text{, }b\geq -4$$