Whakaoti i te x^2-ax+9=0

$$x ^ { 2 } - a x + 9 = 0$$

Whakaoti mō a

$$a=x+\frac{9}{x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-ax+9=-x^{2}$$

Tangohia te 9 mai i ngā taha e rua.

$$-ax=-x^{2}-9$$

He hanga arowhānui tō te whārite.

$$\left(-x\right)a=-x^{2}-9$$

Whakawehea ngā taha e rua ki te -x.

$$\frac{\left(-x\right)a}{-x}=\frac{-x^{2}-9}{-x}$$

Mā te whakawehe ki te -x ka wetekia te whakareanga ki te -x.

$$a=\frac{-x^{2}-9}{-x}$$

Whakawehe -x^{2}-9 ki te -x.

$$a=x+\frac{9}{x}$$

Whakaoti mō x (complex solution)

$$x=\frac{\sqrt{a^{2}-36}+a}{2}$$

$$x=\frac{-\sqrt{a^{2}-36}+a}{2}$$

Whakaoti mō x

$$x=\frac{\sqrt{a^{2}-36}+a}{2}$$

$$x=\frac{-\sqrt{a^{2}-36}+a}{2}\text{, }|a|\geq 6$$