Whakaoti i te x^2-7x+12leq0

$$x ^ { 2 } - 7 x + 12 \leq 0$$

Whakaoti mō x

$$x\in \begin{bmatrix}3,4\end{bmatrix}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Kia whakaotia te koreōrite, me tauwehe te taha mauī. Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$x^{2}-7x+12=0$$

Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -7 mō te b, me te 12 mō te c i te ture pūrua.

$$x=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4\times 1\times 12}}{2}$$

Mahia ngā tātaitai.

$$x=\frac{7±1}{2}$$

Whakaotia te whārite x=\frac{7±1}{2} ina he tōrunga te ±, ina he tōraro te ±.

$$x=4 x=3$$

Tuhia anō te koreōrite mā te whakamahi i ngā otinga i whiwhi.

$$\left(x-4\right)\left(x-3\right)\leq 0$$

Kia ≤0 te otinga, me ≥0 rawa tētahi uara o x-4 me x-3, me ≤0 anō te uara o tētahi. Whakaarohia te tauira ina ko x-4\geq 0 me x-3\leq 0.

$$x-4\geq 0 x-3\leq 0$$

He teka tēnei mō tētahi x ahakoa.

$$x\in \emptyset$$

Whakaarohia te tauira ina ko x-4\leq 0 me x-3\geq 0.

$$x-3\geq 0 x-4\leq 0$$

Te otinga e whakaea i ngā koreōrite e rua ko x\in \left[3,4\right].

$$x\in \begin{bmatrix}3,4\end{bmatrix}$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x\in \begin{bmatrix}3,4\end{bmatrix}$$