Whakaoti i te x^2-5x+2a=0

$$x ^ { 2 } - 5 x + 2 a = 0$$

Whakaoti mō a

$$a=-\frac{x\left(x-5\right)}{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-5x+2a=-x^{2}$$

Me tāpiri te 5x ki ngā taha e rua.

$$2a=-x^{2}+5x$$

He hanga arowhānui tō te whārite.

$$2a=5x-x^{2}$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2a}{2}=\frac{x\left(5-x\right)}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$a=\frac{x\left(5-x\right)}{2}$$

Whakaoti mō x (complex solution)

$$x=\frac{\sqrt{25-8a}+5}{2}$$

$$x=\frac{-\sqrt{25-8a}+5}{2}$$

Whakaoti mō x

$$x=\frac{\sqrt{25-8a}+5}{2}$$

$$x=\frac{-\sqrt{25-8a}+5}{2}\text{, }a\leq \frac{25}{8}$$