Whakaoti i te x^2-5-3=1

$$x ^ { 2 } - 5 - 3 = 1$$

Whakaoti mō x

$$x=3$$

$$x=-3$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 3 i te -5, ka -8.

$$x^{2}-8=1$$

Tangohia te 1 mai i ngā taha e rua.

$$x^{2}-8-1=0$$

Tangohia te 1 i te -8, ka -9.

$$x^{2}-9=0$$

Whakaarohia te x^{2}-9. Tuhia anō te x^{2}-9 hei x^{2}-3^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-3\right)\left(x+3\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-3=0 me te x+3=0.

$$x=3 x=-3$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 3 i te -5, ka -8.

$$x^{2}-8=1$$

Me tāpiri te 8 ki ngā taha e rua.

$$x^{2}=1+8$$

Tāpirihia te 1 ki te 8, ka 9.

$$x^{2}=9$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=3 x=-3$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 3 i te -5, ka -8.

$$x^{2}-8=1$$

Tangohia te 1 mai i ngā taha e rua.

$$x^{2}-8-1=0$$

Tangohia te 1 i te -8, ka -9.

$$x^{2}-9=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -9 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-9\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-9\right)}}{2}$$

Whakareatia -4 ki te -9.

$$x=\frac{0±\sqrt{36}}{2}$$

Tuhia te pūtakerua o te 36.

$$x=\frac{0±6}{2}$$

Nā, me whakaoti te whārite x=\frac{0±6}{2} ina he tāpiri te ±. Whakawehe 6 ki te 2.

$$x=3$$

Nā, me whakaoti te whārite x=\frac{0±6}{2} ina he tango te ±. Whakawehe -6 ki te 2.

$$x=-3$$

Kua oti te whārite te whakatau.

$$x=3 x=-3$$