Whakaoti i te x^2-5=2

$$x ^ { 2 } - 5 = 2$$

Whakaoti mō x

$$x=\sqrt{7}\approx 2.645751311$$

$$x=-\sqrt{7}\approx -2.645751311$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 5 ki ngā taha e rua.

$$x^{2}=2+5$$

Tāpirihia te 2 ki te 5, ka 7.

$$x^{2}=7$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{7} x=-\sqrt{7}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 2 mai i ngā taha e rua.

$$x^{2}-5-2=0$$

Tangohia te 2 i te -5, ka -7.

$$x^{2}-7=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -7 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-7\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-7\right)}}{2}$$

Whakareatia -4 ki te -7.

$$x=\frac{0±\sqrt{28}}{2}$$

Tuhia te pūtakerua o te 28.

$$x=\frac{0±2\sqrt{7}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{7}}{2} ina he tāpiri te ±.

$$x=\sqrt{7}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{7}}{2} ina he tango te ±.

$$x=-\sqrt{7}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{7} x=-\sqrt{7}$$