Whakaoti i te x^2-4xy+x-5=0

$$x ^ { 2 } - 4 x y + x - 5 = 0$$

Whakaoti mō y

$$y=\frac{x}{4}+\frac{1}{4}-\frac{5}{4x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-4xy+x-5=-x^{2}$$

Tangohia te x mai i ngā taha e rua.

$$-4xy-5=-x^{2}-x$$

Me tāpiri te 5 ki ngā taha e rua.

$$-4xy=-x^{2}-x+5$$

He hanga arowhānui tō te whārite.

$$\left(-4x\right)y=5-x-x^{2}$$

Whakawehea ngā taha e rua ki te -4x.

$$\frac{\left(-4x\right)y}{-4x}=\frac{5-x-x^{2}}{-4x}$$

Mā te whakawehe ki te -4x ka wetekia te whakareanga ki te -4x.

$$y=\frac{5-x-x^{2}}{-4x}$$

Whakawehe -x^{2}-x+5 ki te -4x.

$$y=\frac{x}{4}+\frac{1}{4}-\frac{5}{4x}$$

Whakaoti mō x

$$x=\frac{\sqrt{16y^{2}-8y+21}}{2}+2y-\frac{1}{2}$$

$$x=-\frac{\sqrt{16y^{2}-8y+21}}{2}+2y-\frac{1}{2}$$