Whakaoti i te x^2-4x-8y+12=0

$$x ^ { 2 } - 4 x - 8 y + 12 = 0$$

Whakaoti mō y

$$y=\frac{x^{2}-4x+12}{8}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-4x-8y+12=-x^{2}$$

Me tāpiri te 4x ki ngā taha e rua.

$$-8y+12=-x^{2}+4x$$

Tangohia te 12 mai i ngā taha e rua.

$$-8y=-x^{2}+4x-12$$

Whakawehea ngā taha e rua ki te -8.

$$\frac{-8y}{-8}=\frac{-x^{2}+4x-12}{-8}$$

Mā te whakawehe ki te -8 ka wetekia te whakareanga ki te -8.

$$y=\frac{-x^{2}+4x-12}{-8}$$

Whakawehe -x^{2}+4x-12 ki te -8.

$$y=\frac{x^{2}}{8}-\frac{x}{2}+\frac{3}{2}$$

Whakaoti mō x (complex solution)

$$x=2\sqrt{2y-2}+2$$

$$x=-2\sqrt{2y-2}+2$$

Whakaoti mō x

$$x=2\sqrt{2y-2}+2$$

$$x=-2\sqrt{2y-2}+2\text{, }y\geq 1$$