Whakaoti i te x^2-3(x+1)-2[x(x+1)]=-x(x+1)

$$x ^ { 2 } - 3 ( x + 1 ) - 2 [ x ( x + 1 ) ] = - x ( x + 1 )$$

Whakaoti mō x

$$x=-\frac{3}{4}=-0.75$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x+1.

$$x^{2}-3x-3-2x\left(x+1\right)=\left(-x\right)\left(x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -x ki te x+1.

$$x^{2}-3x-3-2x\left(x+1\right)=\left(-x\right)x-x$$

Tangohia te \left(-x\right)x mai i ngā taha e rua.

$$x^{2}-3x-3-2x\left(x+1\right)-\left(-x\right)x=-x$$

Me tāpiri te x ki ngā taha e rua.

$$x^{2}-3x-3-2x\left(x+1\right)-\left(-x\right)x+x=0$$

Whakareatia te -1 ki te 2, ka -2.

$$x^{2}-3x-3-2x\left(x+1\right)-\left(-xx\right)+x=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2x ki te x+1.

$$x^{2}-3x-3-2x^{2}-2x-\left(-xx\right)+x=0$$

Pahekotia te x^{2} me -2x^{2}, ka -x^{2}.

$$-x^{2}-3x-3-2x-\left(-xx\right)+x=0$$

Pahekotia te -3x me -2x, ka -5x.

$$-x^{2}-5x-3-\left(-xx\right)+x=0$$

Whakareatia te x ki te x, ka x^{2}.

$$-x^{2}-5x-3-\left(-x^{2}\right)+x=0$$

Whakareatia te -1 ki te -1, ka 1.

$$-x^{2}-5x-3+x^{2}+x=0$$

Pahekotia te -x^{2} me x^{2}, ka 0.

$$-5x-3+x=0$$

Pahekotia te -5x me x, ka -4x.

$$-4x-3=0$$

Me tāpiri te 3 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$-4x=3$$

Whakawehea ngā taha e rua ki te -4.

$$x=\frac{3}{-4}$$

Ka taea te hautanga \frac{3}{-4} te tuhi anō ko -\frac{3}{4} mā te tango i te tohu tōraro.

$$x=-\frac{3}{4}$$