Whakaoti i te x^2-2x^2+6=2

$$x ^ { 2 } - 2 x ^ { 2 } + 6 = 2$$

Whakaoti mō x

$$x=2$$

$$x=-2$$

Ngā Upane mā te Kimi Pūtakerua

Pahekotia te x^{2} me -2x^{2}, ka -x^{2}.

$$-x^{2}+6=2$$

Tangohia te 6 mai i ngā taha e rua.

$$-x^{2}=2-6$$

Tangohia te 6 i te 2, ka -4.

$$-x^{2}=-4$$

Whakawehea ngā taha e rua ki te -1.

$$x^{2}=\frac{-4}{-1}$$

Ka taea te hautanga \frac{-4}{-1} te whakamāmā ki te 4 mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x^{2}=4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=2 x=-2$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Pahekotia te x^{2} me -2x^{2}, ka -x^{2}.

$$-x^{2}+6=2$$

Tangohia te 2 mai i ngā taha e rua.

$$-x^{2}+6-2=0$$

Tangohia te 2 i te 6, ka 4.

$$-x^{2}+4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -1 mō a, 0 mō b, me 4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 4}}{2\left(-1\right)}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-1\right)\times 4}}{2\left(-1\right)}$$

Whakareatia -4 ki te -1.

$$x=\frac{0±\sqrt{4\times 4}}{2\left(-1\right)}$$

Whakareatia 4 ki te 4.

$$x=\frac{0±\sqrt{16}}{2\left(-1\right)}$$

Tuhia te pūtakerua o te 16.

$$x=\frac{0±4}{2\left(-1\right)}$$

Whakareatia 2 ki te -1.

$$x=\frac{0±4}{-2}$$

Nā, me whakaoti te whārite x=\frac{0±4}{-2} ina he tāpiri te ±. Whakawehe 4 ki te -2.

$$x=-2$$

Nā, me whakaoti te whārite x=\frac{0±4}{-2} ina he tango te ±. Whakawehe -4 ki te -2.

$$x=2$$

Kua oti te whārite te whakatau.

$$x=-2 x=2$$