Whakaoti i te x^2-2ax+1=0

$$x ^ { 2 } - 2 a x + 1 = 0$$

Whakaoti mō a

$$a=\frac{x}{2}+\frac{1}{2x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-2ax+1=-x^{2}$$

Tangohia te 1 mai i ngā taha e rua.

$$-2ax=-x^{2}-1$$

He hanga arowhānui tō te whārite.

$$\left(-2x\right)a=-x^{2}-1$$

Whakawehea ngā taha e rua ki te -2x.

$$\frac{\left(-2x\right)a}{-2x}=\frac{-x^{2}-1}{-2x}$$

Mā te whakawehe ki te -2x ka wetekia te whakareanga ki te -2x.

$$a=\frac{-x^{2}-1}{-2x}$$

Whakawehe -x^{2}-1 ki te -2x.

$$a=\frac{x}{2}+\frac{1}{2x}$$

Whakaoti mō x (complex solution)

$$x=\sqrt{a^{2}-1}+a$$

$$x=-\sqrt{a^{2}-1}+a$$

Whakaoti mō x

$$x=\sqrt{a^{2}-1}+a$$

$$x=-\sqrt{a^{2}-1}+a\text{, }|a|\geq 1$$