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x^{2}\geq 18
Me tāpiri te 18 ki ngā taha e rua.
x^{2}\geq \left(3\sqrt{2}\right)^{2}
Tātaitia te pūtakerua o 18 kia tae ki 3\sqrt{2}. Tuhia anō te 18 hei \left(3\sqrt{2}\right)^{2}.
|x|\geq 3\sqrt{2}
E mau ana te koreōrite mō |x|\geq 3\sqrt{2}.
x\leq -3\sqrt{2}\text{; }x\geq 3\sqrt{2}
Tuhia anō te |x|\geq 3\sqrt{2} hei x\leq -3\sqrt{2}\text{; }x\geq 3\sqrt{2}.