Whakaoti i te x^2-12=1

$$x ^ { 2 } - 12 = 1$$

Whakaoti mō x

$$x=\sqrt{13}\approx 3.605551275$$

$$x=-\sqrt{13}\approx -3.605551275$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 12 ki ngā taha e rua.

$$x^{2}=1+12$$

Tāpirihia te 1 ki te 12, ka 13.

$$x^{2}=13$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{13} x=-\sqrt{13}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$x^{2}-12-1=0$$

Tangohia te 1 i te -12, ka -13.

$$x^{2}-13=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -13 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-13\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-13\right)}}{2}$$

Whakareatia -4 ki te -13.

$$x=\frac{0±\sqrt{52}}{2}$$

Tuhia te pūtakerua o te 52.

$$x=\frac{0±2\sqrt{13}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{13}}{2} ina he tāpiri te ±.

$$x=\sqrt{13}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{13}}{2} ina he tango te ±.

$$x=-\sqrt{13}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{13} x=-\sqrt{13}$$