Whakaoti i te x^2-10x-24

$$x ^ { 2 } - 10 x - 24$$

Tauwehe

$$\left(x-12\right)\left(x+2\right)$$

Ngā Upane Otinga

Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei x^{2}+ax+bx-24. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-10 ab=1\left(-24\right)=-24$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōraro te a+b, he nui ake te uara pū o te tau tōraro i tō te tōrunga. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -24.

$$1,-24 2,-12 3,-8 4,-6$$

Tātaihia te tapeke mō ia takirua.

$$1-24=-23 2-12=-10 3-8=-5 4-6=-2$$

Ko te otinga te takirua ka hoatu i te tapeke -10.

$$a=-12 b=2$$

Tuhia anō te x^{2}-10x-24 hei \left(x^{2}-12x\right)+\left(2x-24\right).

$$\left(x^{2}-12x\right)+\left(2x-24\right)$$

Tauwehea te x i te tuatahi me te 2 i te rōpū tuarua.

$$x\left(x-12\right)+2\left(x-12\right)$$

Whakatauwehea atu te kīanga pātahi x-12 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-12\right)\left(x+2\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$x^{2}-10x-24=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}-4\left(-24\right)}}{2}$$

Pūrua -10.

$$x=\frac{-\left(-10\right)±\sqrt{100-4\left(-24\right)}}{2}$$

Whakareatia -4 ki te -24.

$$x=\frac{-\left(-10\right)±\sqrt{100+96}}{2}$$

Tāpiri 100 ki te 96.

$$x=\frac{-\left(-10\right)±\sqrt{196}}{2}$$

Tuhia te pūtakerua o te 196.

$$x=\frac{-\left(-10\right)±14}{2}$$

Ko te tauaro o -10 ko 10.

$$x=\frac{10±14}{2}$$

Nā, me whakaoti te whārite x=\frac{10±14}{2} ina he tāpiri te ±. Tāpiri 10 ki te 14.

$$x=\frac{24}{2}$$

Whakawehe 24 ki te 2.

$$x=12$$

Nā, me whakaoti te whārite x=\frac{10±14}{2} ina he tango te ±. Tango 14 mai i 10.

$$x=-\frac{4}{2}$$

Whakawehe -4 ki te 2.

$$x=-2$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 12 mō te x_{1} me te -2 mō te x_{2}.

$$x^{2}-10x-24=\left(x-12\right)\left(x-\left(-2\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$x^{2}-10x-24=\left(x-12\right)\left(x+2\right)$$

Aromātai

$$\left(x-12\right)\left(x+2\right)$$