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\left(-5+x-b\right)\left(-5+x+b\right)
Tuhia anō te x^{2}-10x+25-b^{2} hei \left(-5+x\right)^{2}-b^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\left(x-b-5\right)\left(x+b-5\right)
Whakaraupapatia anō ngā kīanga tau.