Whakaoti mō x
x=5
Graph
Tohaina
Kua tāruatia ki te papatopenga
x^{2}-10x+25=0
Kia whakaotia te koreōrite, me tauwehe te taha mauī. Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.
x=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}-4\times 1\times 25}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -10 mō te b, me te 25 mō te c i te ture pūrua.
x=\frac{10±0}{2}
Mahia ngā tātaitai.
x=5
He ōrite ngā whakatau.
\left(x-5\right)^{2}\leq 0
Tuhia anō te koreōrite mā te whakamahi i ngā otinga i whiwhi.
x=5
E mau ana te koreōrite mō x=5.
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