Whakaoti i te x^2-10x+25=7

$$x ^ { 2 } - 10 x + 25 = 7$$

Whakaoti mō x

$$x=\sqrt{7}+5\approx 7.645751311$$

$$x=5-\sqrt{7}\approx 2.354248689$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x^{2}-10x+25=7$$

Me tango 7 mai i ngā taha e rua o te whārite.

$$x^{2}-10x+25-7=7-7$$

Mā te tango i te 7 i a ia ake anō ka toe ko te 0.

$$x^{2}-10x+25-7=0$$

Tango 7 mai i 25.

$$x^{2}-10x+18=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -10 mō b, me 18 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}-4\times 18}}{2}$$

Pūrua -10.

$$x=\frac{-\left(-10\right)±\sqrt{100-4\times 18}}{2}$$

Whakareatia -4 ki te 18.

$$x=\frac{-\left(-10\right)±\sqrt{100-72}}{2}$$

Tāpiri 100 ki te -72.

$$x=\frac{-\left(-10\right)±\sqrt{28}}{2}$$

Tuhia te pūtakerua o te 28.

$$x=\frac{-\left(-10\right)±2\sqrt{7}}{2}$$

Ko te tauaro o -10 ko 10.

$$x=\frac{10±2\sqrt{7}}{2}$$

Nā, me whakaoti te whārite x=\frac{10±2\sqrt{7}}{2} ina he tāpiri te ±. Tāpiri 10 ki te 2\sqrt{7}.

$$x=\frac{2\sqrt{7}+10}{2}$$

Whakawehe 10+2\sqrt{7} ki te 2.

$$x=\sqrt{7}+5$$

Nā, me whakaoti te whārite x=\frac{10±2\sqrt{7}}{2} ina he tango te ±. Tango 2\sqrt{7} mai i 10.

$$x=\frac{10-2\sqrt{7}}{2}$$

Whakawehe 10-2\sqrt{7} ki te 2.

$$x=5-\sqrt{7}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{7}+5 x=5-\sqrt{7}$$

Ngā Upane mō te Whakaoti i te Pūrua

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$x^{2}-10x+25=7$$

Tauwehea x^{2}-10x+25. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-5\right)^{2}=7$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-5\right)^{2}}=\sqrt{7}$$

Whakarūnātia.

$$x-5=\sqrt{7} x-5=-\sqrt{7}$$

Me tāpiri 5 ki ngā taha e rua o te whārite.

$$x=\sqrt{7}+5 x=5-\sqrt{7}$$