Whakaoti i te x^2-10x+0

$$x ^ { 2 } - 10 x + 0$$

Tauwehe

$$x\left(x-10\right)$$

Ngā Upane Otinga

Tauwehea te x.

$$x\left(x-10\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$x^{2}-10x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}}}{2}$$

Tuhia te pūtakerua o te \left(-10\right)^{2}.

$$x=\frac{-\left(-10\right)±10}{2}$$

Ko te tauaro o -10 ko 10.

$$x=\frac{10±10}{2}$$

Nā, me whakaoti te whārite x=\frac{10±10}{2} ina he tāpiri te ±. Tāpiri 10 ki te 10.

$$x=\frac{20}{2}$$

Whakawehe 20 ki te 2.

$$x=10$$

Nā, me whakaoti te whārite x=\frac{10±10}{2} ina he tango te ±. Tango 10 mai i 10.

$$x=\frac{0}{2}$$

Whakawehe 0 ki te 2.

$$x=0$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 10 mō te x_{1} me te 0 mō te x_{2}.

$$x^{2}-10x=\left(x-10\right)x$$

Aromātai

$$x\left(x-10\right)$$

Ngā Upane Otinga

Ko te tau i tāpiria he kore ka hua koia tonu.

$$x^{2}-10x$$