Whakaoti i te x^2-10=-12

$$x ^ { 2 } - 10 = - 12$$

Whakaoti mō x (complex solution)

$$x=-\sqrt{2}i\approx -0-1.414213562i$$

$$x=\sqrt{2}i\approx 1.414213562i$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 10 ki ngā taha e rua.

$$x^{2}=-12+10$$

Tāpirihia te -12 ki te 10, ka -2.

$$x^{2}=-2$$

Kua oti te whārite te whakatau.

$$x=\sqrt{2}i x=-\sqrt{2}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 12 ki ngā taha e rua.

$$x^{2}-10+12=0$$

Tāpirihia te -10 ki te 12, ka 2.

$$x^{2}+2=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 2 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 2}}{2}$$

Whakareatia -4 ki te 2.

$$x=\frac{0±\sqrt{-8}}{2}$$

Tuhia te pūtakerua o te -8.

$$x=\frac{0±2\sqrt{2}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2}i}{2} ina he tāpiri te ±.

$$x=\sqrt{2}i$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2}i}{2} ina he tango te ±.

$$x=-\sqrt{2}i$$

Kua oti te whārite te whakatau.

$$x=\sqrt{2}i x=-\sqrt{2}i$$