Whakaoti i te x^2-(x-1)^2=25

$$x ^ { 2 } - ( x - 1 ) ^ { 2 } = 25$$

Whakaoti mō x

$$x=13$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-1\right)^{2}.

$$x^{2}-\left(x^{2}-2x+1\right)=25$$

Hei kimi i te tauaro o x^{2}-2x+1, kimihia te tauaro o ia taurangi.

$$x^{2}-x^{2}+2x-1=25$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$2x-1=25$$

Me tāpiri te 1 ki ngā taha e rua.

$$2x=25+1$$

Tāpirihia te 25 ki te 1, ka 26.

$$2x=26$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{26}{2}$$

Whakawehea te 26 ki te 2, kia riro ko 13.

$$x=13$$