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x^{2}\geq \left(2\sqrt{10}\right)^{2}
Tātaitia te pūtakerua o 40 kia tae ki 2\sqrt{10}. Tuhia anō te 40 hei \left(2\sqrt{10}\right)^{2}.
|x|\geq 2\sqrt{10}
E mau ana te koreōrite mō |x|\geq 2\sqrt{10}.
x\leq -2\sqrt{10}\text{; }x\geq 2\sqrt{10}
Tuhia anō te |x|\geq 2\sqrt{10} hei x\leq -2\sqrt{10}\text{; }x\geq 2\sqrt{10}.