Whakaoti i te x^2>-4x

$$x ^ { 2 } > - 4 x$$

Whakaoti mō x

$$x\in \left(-\infty,-4\right)\cup \left(0,\infty\right)$$

Ngā Upane Otinga

Me tāpiri te 4x ki ngā taha e rua.

$$x^{2}+4x>0$$

Tauwehea te x.

$$x\left(x+4\right)>0$$

Kia tōrunga te otinga, me tōraro tahi te x+4 me te x, me tōrunga tahi rānei. Whakaarohia te tauira ina he tōraro tahi te x+4 me te x.

$$x+4<0 x<0$$

Te otinga e whakaea i ngā koreōrite e rua ko x<-4.

$$x<-4$$

Whakaarohia te tauira ina he tōrunga tahi te x+4 me te x.

$$x>0 x+4>0$$

Te otinga e whakaea i ngā koreōrite e rua ko x>0.

$$x>0$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x<-4\text{; }x>0$$