Whakaoti i te x^2=8x

$$x ^ { 2 } = 8 x$$

Whakaoti mō x

$$x=8$$

$$x=0$$

Ngā Upane Whakamahi Tauwehe

Tangohia te 8x mai i ngā taha e rua.

$$x^{2}-8x=0$$

Tauwehea te x.

$$x\left(x-8\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te x-8=0.

$$x=0 x=8$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 8x mai i ngā taha e rua.

$$x^{2}-8x=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -8 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}}}{2}$$

Tuhia te pūtakerua o te \left(-8\right)^{2}.

$$x=\frac{-\left(-8\right)±8}{2}$$

Ko te tauaro o -8 ko 8.

$$x=\frac{8±8}{2}$$

Nā, me whakaoti te whārite x=\frac{8±8}{2} ina he tāpiri te ±. Tāpiri 8 ki te 8.

$$x=\frac{16}{2}$$

Whakawehe 16 ki te 2.

$$x=8$$

Nā, me whakaoti te whārite x=\frac{8±8}{2} ina he tango te ±. Tango 8 mai i 8.

$$x=\frac{0}{2}$$

Whakawehe 0 ki te 2.

$$x=0$$

Kua oti te whārite te whakatau.

$$x=8 x=0$$

Ngā Upane mō te Whakaoti i te Pūrua

Tangohia te 8x mai i ngā taha e rua.

$$x^{2}-8x=0$$

Whakawehea te -8, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -4. Nā, tāpiria te pūrua o te -4 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-8x+\left(-4\right)^{2}=\left(-4\right)^{2}$$

Pūrua -4.

$$x^{2}-8x+16=16$$

Tauwehea x^{2}-8x+16. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-4\right)^{2}=16$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-4\right)^{2}}=\sqrt{16}$$

Whakarūnātia.

$$x-4=4 x-4=-4$$

Me tāpiri 4 ki ngā taha e rua o te whārite.

$$x=8 x=0$$