Whakaoti i te x^2=78

$$x ^ { 2 } = 78$$

Whakaoti mō x

$$x=\sqrt{78}\approx 8.831760866$$

$$x=-\sqrt{78}\approx -8.831760866$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{78} x=-\sqrt{78}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 78 mai i ngā taha e rua.

$$x^{2}-78=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -78 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-78\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-78\right)}}{2}$$

Whakareatia -4 ki te -78.

$$x=\frac{0±\sqrt{312}}{2}$$

Tuhia te pūtakerua o te 312.

$$x=\frac{0±2\sqrt{78}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{78}}{2} ina he tāpiri te ±.

$$x=\sqrt{78}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{78}}{2} ina he tango te ±.

$$x=-\sqrt{78}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{78} x=-\sqrt{78}$$