Whakaoti i te x^2=7^2+16

$$x ^ { 2 } = 7 ^ { 2 } + 16$$

Whakaoti mō x

$$x=\sqrt{65}\approx 8.062257748$$

$$x=-\sqrt{65}\approx -8.062257748$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 7 mā te pū o 2, kia riro ko 49.

$$x^{2}=49+16$$

Tāpirihia te 49 ki te 16, ka 65.

$$x^{2}=65$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{65} x=-\sqrt{65}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 7 mā te pū o 2, kia riro ko 49.

$$x^{2}=49+16$$

Tāpirihia te 49 ki te 16, ka 65.

$$x^{2}=65$$

Tangohia te 65 mai i ngā taha e rua.

$$x^{2}-65=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -65 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-65\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-65\right)}}{2}$$

Whakareatia -4 ki te -65.

$$x=\frac{0±\sqrt{260}}{2}$$

Tuhia te pūtakerua o te 260.

$$x=\frac{0±2\sqrt{65}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{65}}{2} ina he tāpiri te ±.

$$x=\sqrt{65}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{65}}{2} ina he tango te ±.

$$x=-\sqrt{65}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{65} x=-\sqrt{65}$$