Whakaoti i te x^2=6+6

$$x ^ { 2 } = 6 + 6$$

Whakaoti mō x

$$x=2\sqrt{3}\approx 3.464101615$$

$$x=-2\sqrt{3}\approx -3.464101615$$

Ngā Upane mā te Kimi Pūtakerua

Tāpirihia te 6 ki te 6, ka 12.

$$x^{2}=12$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=2\sqrt{3} x=-2\sqrt{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tāpirihia te 6 ki te 6, ka 12.

$$x^{2}=12$$

Tangohia te 12 mai i ngā taha e rua.

$$x^{2}-12=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -12 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-12\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-12\right)}}{2}$$

Whakareatia -4 ki te -12.

$$x=\frac{0±\sqrt{48}}{2}$$

Tuhia te pūtakerua o te 48.

$$x=\frac{0±4\sqrt{3}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{3}}{2} ina he tāpiri te ±.

$$x=2\sqrt{3}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{3}}{2} ina he tango te ±.

$$x=-2\sqrt{3}$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{3} x=-2\sqrt{3}$$