Whakaoti i te x^2=5*2

$$x ^ { 2 } = 5 \cdot 2$$

Whakaoti mō x

$$x=\sqrt{10}\approx 3.16227766$$

$$x=-\sqrt{10}\approx -3.16227766$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te 5 ki te 2, ka 10.

$$x^{2}=10$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{10} x=-\sqrt{10}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te 5 ki te 2, ka 10.

$$x^{2}=10$$

Tangohia te 10 mai i ngā taha e rua.

$$x^{2}-10=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -10 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-10\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-10\right)}}{2}$$

Whakareatia -4 ki te -10.

$$x=\frac{0±\sqrt{40}}{2}$$

Tuhia te pūtakerua o te 40.

$$x=\frac{0±2\sqrt{10}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{10}}{2} ina he tāpiri te ±.

$$x=\sqrt{10}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{10}}{2} ina he tango te ±.

$$x=-\sqrt{10}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{10} x=-\sqrt{10}$$