Whakaoti i te x^2=42

$$x ^ { 2 } = 42$$

Whakaoti mō x

$$x=\sqrt{42}\approx 6.480740698$$

$$x=-\sqrt{42}\approx -6.480740698$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{42} x=-\sqrt{42}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 42 mai i ngā taha e rua.

$$x^{2}-42=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -42 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-42\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-42\right)}}{2}$$

Whakareatia -4 ki te -42.

$$x=\frac{0±\sqrt{168}}{2}$$

Tuhia te pūtakerua o te 168.

$$x=\frac{0±2\sqrt{42}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{42}}{2} ina he tāpiri te ±.

$$x=\sqrt{42}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{42}}{2} ina he tango te ±.

$$x=-\sqrt{42}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{42} x=-\sqrt{42}$$