Whakaoti i te x^2=289

$$x ^ { 2 } = 289$$

Whakaoti mō x

$$x=17$$

$$x=-17$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 289 mai i ngā taha e rua.

$$x^{2}-289=0$$

Whakaarohia te x^{2}-289. Tuhia anō te x^{2}-289 hei x^{2}-17^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-17\right)\left(x+17\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-17=0 me te x+17=0.

$$x=17 x=-17$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=17 x=-17$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 289 mai i ngā taha e rua.

$$x^{2}-289=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -289 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-289\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-289\right)}}{2}$$

Whakareatia -4 ki te -289.

$$x=\frac{0±\sqrt{1156}}{2}$$

Tuhia te pūtakerua o te 1156.

$$x=\frac{0±34}{2}$$

Nā, me whakaoti te whārite x=\frac{0±34}{2} ina he tāpiri te ±. Whakawehe 34 ki te 2.

$$x=17$$

Nā, me whakaoti te whārite x=\frac{0±34}{2} ina he tango te ±. Whakawehe -34 ki te 2.

$$x=-17$$

Kua oti te whārite te whakatau.

$$x=17 x=-17$$