Whakaoti i te x^2=12^2-6^2

$$x ^ { 2 } = 12 ^ { 2 } - 6 ^ { 2 }$$

Whakaoti mō x

$$x=6\sqrt{3}\approx 10.392304845$$

$$x=-6\sqrt{3}\approx -10.392304845$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 12 mā te pū o 2, kia riro ko 144.

$$x^{2}=144-6^{2}$$

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$x^{2}=144-36$$

Tangohia te 36 i te 144, ka 108.

$$x^{2}=108$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=6\sqrt{3} x=-6\sqrt{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 12 mā te pū o 2, kia riro ko 144.

$$x^{2}=144-6^{2}$$

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$x^{2}=144-36$$

Tangohia te 36 i te 144, ka 108.

$$x^{2}=108$$

Tangohia te 108 mai i ngā taha e rua.

$$x^{2}-108=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -108 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-108\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-108\right)}}{2}$$

Whakareatia -4 ki te -108.

$$x=\frac{0±\sqrt{432}}{2}$$

Tuhia te pūtakerua o te 432.

$$x=\frac{0±12\sqrt{3}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±12\sqrt{3}}{2} ina he tāpiri te ±.

$$x=6\sqrt{3}$$

Nā, me whakaoti te whārite x=\frac{0±12\sqrt{3}}{2} ina he tango te ±.

$$x=-6\sqrt{3}$$

Kua oti te whārite te whakatau.

$$x=6\sqrt{3} x=-6\sqrt{3}$$