Whakaoti i te x^2=1.62

$$x ^ { 2 } = 1.62$$

Whakaoti mō x

$$x = \frac{9 \sqrt{2}}{10} \approx 1.272792206$$

$$x = -\frac{9 \sqrt{2}}{10} \approx -1.272792206$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{9\sqrt{2}}{10} x=-\frac{9\sqrt{2}}{10}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 1.62 mai i ngā taha e rua.

$$x^{2}-1.62=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1.62 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1.62\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-1.62\right)}}{2}$$

Whakareatia -4 ki te -1.62.

$$x=\frac{0±\sqrt{6.48}}{2}$$

Tuhia te pūtakerua o te 6.48.

$$x=\frac{0±\frac{9\sqrt{2}}{5}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{9\sqrt{2}}{5}}{2} ina he tāpiri te ±.

$$x=\frac{9\sqrt{2}}{10}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{9\sqrt{2}}{5}}{2} ina he tango te ±.

$$x=-\frac{9\sqrt{2}}{10}$$

Kua oti te whārite te whakatau.

$$x=\frac{9\sqrt{2}}{10} x=-\frac{9\sqrt{2}}{10}$$