Whakaoti i te x^2=1.21

$$x ^ { 2 } = 1.21$$

Whakaoti mō x

$$x=1.1$$

$$x=-1.1$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 1.21 mai i ngā taha e rua.

$$x^{2}-1.21=0$$

Whakaarohia te x^{2}-1.21. Tuhia anō te x^{2}-1.21 hei x^{2}-\left(\frac{11}{10}\right)^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-\frac{11}{10}\right)\left(x+\frac{11}{10}\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-\frac{11}{10}=0 me te x+\frac{11}{10}=0.

$$x=\frac{11}{10} x=-\frac{11}{10}$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{11}{10} x=-\frac{11}{10}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 1.21 mai i ngā taha e rua.

$$x^{2}-1.21=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1.21 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1.21\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-1.21\right)}}{2}$$

Whakareatia -4 ki te -1.21.

$$x=\frac{0±\sqrt{4.84}}{2}$$

Tuhia te pūtakerua o te 4.84.

$$x=\frac{0±\frac{11}{5}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{11}{5}}{2} ina he tāpiri te ±.

$$x=\frac{11}{10}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{11}{5}}{2} ina he tango te ±.

$$x=-\frac{11}{10}$$

Kua oti te whārite te whakatau.

$$x=\frac{11}{10} x=-\frac{11}{10}$$