Whakaoti i te x^2=-16

$$x ^ { 2 } = - 16$$

Whakaoti mō x (complex solution)

$$x=-4i$$

$$x=4i$$

Ngā Upane mā te Kimi Pūtakerua

Kua oti te whārite te whakatau.

$$x=4i x=-4i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 16 ki ngā taha e rua.

$$x^{2}+16=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 16 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 16}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 16}}{2}$$

Whakareatia -4 ki te 16.

$$x=\frac{0±\sqrt{-64}}{2}$$

Tuhia te pūtakerua o te -64.

$$x=\frac{0±8i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±8i}{2} ina he tāpiri te ±.

$$x=4i$$

Nā, me whakaoti te whārite x=\frac{0±8i}{2} ina he tango te ±.

$$x=-4i$$

Kua oti te whārite te whakatau.

$$x=4i x=-4i$$