Whakaoti i te x^2=-125

$$x ^ { 2 } = - 125$$

Whakaoti mō x (complex solution)

$$x=-5\sqrt{5}i\approx -0-11.180339887i$$

$$x=5\sqrt{5}i\approx 11.180339887i$$

Ngā Upane mā te Kimi Pūtakerua

Kua oti te whārite te whakatau.

$$x=5\sqrt{5}i x=-5\sqrt{5}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 125 ki ngā taha e rua.

$$x^{2}+125=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 125 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 125}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 125}}{2}$$

Whakareatia -4 ki te 125.

$$x=\frac{0±\sqrt{-500}}{2}$$

Tuhia te pūtakerua o te -500.

$$x=\frac{0±10\sqrt{5}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±10\sqrt{5}i}{2} ina he tāpiri te ±.

$$x=5\sqrt{5}i$$

Nā, me whakaoti te whārite x=\frac{0±10\sqrt{5}i}{2} ina he tango te ±.

$$x=-5\sqrt{5}i$$

Kua oti te whārite te whakatau.

$$x=5\sqrt{5}i x=-5\sqrt{5}i$$