Whakaoti i te x^2=4a/sqrt{3}

$$x ^ { 2 } = \frac { 4 a } { \sqrt { 3 } }$$

Whakaoti mō a

$$a=\frac{\sqrt{3}x^{2}}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakangāwaritia te tauraro o \frac{4a}{\sqrt{3}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{3}.

$$x^{2}=\frac{4a\sqrt{3}}{\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{3} ko 3.

$$x^{2}=\frac{4a\sqrt{3}}{3}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{4a\sqrt{3}}{3}=x^{2}$$

Whakareatia ngā taha e rua o te whārite ki te 3.

$$4a\sqrt{3}=3x^{2}$$

He hanga arowhānui tō te whārite.

$$4\sqrt{3}a=3x^{2}$$

Whakawehea ngā taha e rua ki te 4\sqrt{3}.

$$\frac{4\sqrt{3}a}{4\sqrt{3}}=\frac{3x^{2}}{4\sqrt{3}}$$

Mā te whakawehe ki te 4\sqrt{3} ka wetekia te whakareanga ki te 4\sqrt{3}.

$$a=\frac{3x^{2}}{4\sqrt{3}}$$

Whakawehe 3x^{2} ki te 4\sqrt{3}.

$$a=\frac{\sqrt{3}x^{2}}{4}$$

Whakaoti mō x (complex solution)

$$x=-\frac{2\times 3^{\frac{3}{4}}\sqrt{a}}{3}$$

$$x=\frac{2\times 3^{\frac{3}{4}}\sqrt{a}}{3}$$

Whakaoti mō x

$$x=\frac{2\times 3^{\frac{3}{4}}\sqrt{a}}{3}$$

$$x=-\frac{2\times 3^{\frac{3}{4}}\sqrt{a}}{3}\text{, }a\geq 0$$