Whakaoti i te x^2+9=13

$$x ^ { 2 } + 9 = 13$$

Whakaoti mō x

$$x=2$$

$$x=-2$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 13 mai i ngā taha e rua.

$$x^{2}+9-13=0$$

Tangohia te 13 i te 9, ka -4.

$$x^{2}-4=0$$

Whakaarohia te x^{2}-4. Tuhia anō te x^{2}-4 hei x^{2}-2^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-2\right)\left(x+2\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-2=0 me te x+2=0.

$$x=2 x=-2$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 9 mai i ngā taha e rua.

$$x^{2}=13-9$$

Tangohia te 9 i te 13, ka 4.

$$x^{2}=4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=2 x=-2$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 13 mai i ngā taha e rua.

$$x^{2}+9-13=0$$

Tangohia te 13 i te 9, ka -4.

$$x^{2}-4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-4\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-4\right)}}{2}$$

Whakareatia -4 ki te -4.

$$x=\frac{0±\sqrt{16}}{2}$$

Tuhia te pūtakerua o te 16.

$$x=\frac{0±4}{2}$$

Nā, me whakaoti te whārite x=\frac{0±4}{2} ina he tāpiri te ±. Whakawehe 4 ki te 2.

$$x=2$$

Nā, me whakaoti te whārite x=\frac{0±4}{2} ina he tango te ±. Whakawehe -4 ki te 2.

$$x=-2$$

Kua oti te whārite te whakatau.

$$x=2 x=-2$$