Whakaoti i te x^2+76=400

$$x ^ { 2 } + 76 = 400$$

Whakaoti mō x

$$x=18$$

$$x=-18$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 400 mai i ngā taha e rua.

$$x^{2}+76-400=0$$

Tangohia te 400 i te 76, ka -324.

$$x^{2}-324=0$$

Whakaarohia te x^{2}-324. Tuhia anō te x^{2}-324 hei x^{2}-18^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-18\right)\left(x+18\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-18=0 me te x+18=0.

$$x=18 x=-18$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 76 mai i ngā taha e rua.

$$x^{2}=400-76$$

Tangohia te 76 i te 400, ka 324.

$$x^{2}=324$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=18 x=-18$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 400 mai i ngā taha e rua.

$$x^{2}+76-400=0$$

Tangohia te 400 i te 76, ka -324.

$$x^{2}-324=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -324 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-324\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-324\right)}}{2}$$

Whakareatia -4 ki te -324.

$$x=\frac{0±\sqrt{1296}}{2}$$

Tuhia te pūtakerua o te 1296.

$$x=\frac{0±36}{2}$$

Nā, me whakaoti te whārite x=\frac{0±36}{2} ina he tāpiri te ±. Whakawehe 36 ki te 2.

$$x=18$$

Nā, me whakaoti te whārite x=\frac{0±36}{2} ina he tango te ±. Whakawehe -36 ki te 2.

$$x=-18$$

Kua oti te whārite te whakatau.

$$x=18 x=-18$$