Whakaoti i te x^2+7x-3

$$x ^ { 2 } + 7 x - 3$$

Tauwehe

$$\left(x-\frac{-\sqrt{61}-7}{2}\right)\left(x-\frac{\sqrt{61}-7}{2}\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$x^{2}+7x-3=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-7±\sqrt{7^{2}-4\left(-3\right)}}{2}$$

Pūrua 7.

$$x=\frac{-7±\sqrt{49-4\left(-3\right)}}{2}$$

Whakareatia -4 ki te -3.

$$x=\frac{-7±\sqrt{49+12}}{2}$$

Tāpiri 49 ki te 12.

$$x=\frac{-7±\sqrt{61}}{2}$$

Nā, me whakaoti te whārite x=\frac{-7±\sqrt{61}}{2} ina he tāpiri te ±. Tāpiri -7 ki te \sqrt{61}.

$$x=\frac{\sqrt{61}-7}{2}$$

Nā, me whakaoti te whārite x=\frac{-7±\sqrt{61}}{2} ina he tango te ±. Tango \sqrt{61} mai i -7.

$$x=\frac{-\sqrt{61}-7}{2}$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te \frac{-7+\sqrt{61}}{2} mō te x_{1} me te \frac{-7-\sqrt{61}}{2} mō te x_{2}.

$$x^{2}+7x-3=\left(x-\frac{\sqrt{61}-7}{2}\right)\left(x-\frac{-\sqrt{61}-7}{2}\right)$$

Aromātai

$$x^{2}+7x-3$$