Whakaoti i te x^2+6x-16=6x

$$x ^ { 2 } + 6 x - 16 = 6 x$$

Whakaoti mō x

$$x=4$$

$$x=-4$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 6x mai i ngā taha e rua.

$$x^{2}+6x-16-6x=0$$

Pahekotia te 6x me -6x, ka 0.

$$x^{2}-16=0$$

Whakaarohia te x^{2}-16. Tuhia anō te x^{2}-16 hei x^{2}-4^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-4\right)\left(x+4\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-4=0 me te x+4=0.

$$x=4 x=-4$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 6x mai i ngā taha e rua.

$$x^{2}+6x-16-6x=0$$

Pahekotia te 6x me -6x, ka 0.

$$x^{2}-16=0$$

Me tāpiri te 16 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$x^{2}=16$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=4 x=-4$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 6x mai i ngā taha e rua.

$$x^{2}+6x-16-6x=0$$

Pahekotia te 6x me -6x, ka 0.

$$x^{2}-16=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -16 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-16\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-16\right)}}{2}$$

Whakareatia -4 ki te -16.

$$x=\frac{0±\sqrt{64}}{2}$$

Tuhia te pūtakerua o te 64.

$$x=\frac{0±8}{2}$$

Nā, me whakaoti te whārite x=\frac{0±8}{2} ina he tāpiri te ±. Whakawehe 8 ki te 2.

$$x=4$$

Nā, me whakaoti te whārite x=\frac{0±8}{2} ina he tango te ±. Whakawehe -8 ki te 2.

$$x=-4$$

Kua oti te whārite te whakatau.

$$x=4 x=-4$$