Whakaoti i te x^2+6=262

$$x ^ { 2 } + 6 = 262$$

Whakaoti mō x

$$x=16$$

$$x=-16$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 262 mai i ngā taha e rua.

$$x^{2}+6-262=0$$

Tangohia te 262 i te 6, ka -256.

$$x^{2}-256=0$$

Whakaarohia te x^{2}-256. Tuhia anō te x^{2}-256 hei x^{2}-16^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-16\right)\left(x+16\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-16=0 me te x+16=0.

$$x=16 x=-16$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 6 mai i ngā taha e rua.

$$x^{2}=262-6$$

Tangohia te 6 i te 262, ka 256.

$$x^{2}=256$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=16 x=-16$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 262 mai i ngā taha e rua.

$$x^{2}+6-262=0$$

Tangohia te 262 i te 6, ka -256.

$$x^{2}-256=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -256 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-256\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-256\right)}}{2}$$

Whakareatia -4 ki te -256.

$$x=\frac{0±\sqrt{1024}}{2}$$

Tuhia te pūtakerua o te 1024.

$$x=\frac{0±32}{2}$$

Nā, me whakaoti te whārite x=\frac{0±32}{2} ina he tāpiri te ±. Whakawehe 32 ki te 2.

$$x=16$$

Nā, me whakaoti te whārite x=\frac{0±32}{2} ina he tango te ±. Whakawehe -32 ki te 2.

$$x=-16$$

Kua oti te whārite te whakatau.

$$x=16 x=-16$$