Whakaoti i te x^2+5=149

$$x ^ { 2 } + 5 = 149$$

Whakaoti mō x

$$x=12$$

$$x=-12$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 149 mai i ngā taha e rua.

$$x^{2}+5-149=0$$

Tangohia te 149 i te 5, ka -144.

$$x^{2}-144=0$$

Whakaarohia te x^{2}-144. Tuhia anō te x^{2}-144 hei x^{2}-12^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-12\right)\left(x+12\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-12=0 me te x+12=0.

$$x=12 x=-12$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 5 mai i ngā taha e rua.

$$x^{2}=149-5$$

Tangohia te 5 i te 149, ka 144.

$$x^{2}=144$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=12 x=-12$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 149 mai i ngā taha e rua.

$$x^{2}+5-149=0$$

Tangohia te 149 i te 5, ka -144.

$$x^{2}-144=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -144 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-144\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-144\right)}}{2}$$

Whakareatia -4 ki te -144.

$$x=\frac{0±\sqrt{576}}{2}$$

Tuhia te pūtakerua o te 576.

$$x=\frac{0±24}{2}$$

Nā, me whakaoti te whārite x=\frac{0±24}{2} ina he tāpiri te ±. Whakawehe 24 ki te 2.

$$x=12$$

Nā, me whakaoti te whārite x=\frac{0±24}{2} ina he tango te ±. Whakawehe -24 ki te 2.

$$x=-12$$

Kua oti te whārite te whakatau.

$$x=12 x=-12$$