Whakaoti i te x^2+4xy=5y

$$x ^ { 2 } + 4 x y = 5 y$$

Whakaoti mō y

$$y=-\frac{x^{2}}{4x-5}$$

$$x\neq \frac{5}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 5y mai i ngā taha e rua.

$$x^{2}+4xy-5y=0$$

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$4xy-5y=-x^{2}$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(4x-5\right)y=-x^{2}$$

Whakawehea ngā taha e rua ki te 4x-5.

$$\frac{\left(4x-5\right)y}{4x-5}=-\frac{x^{2}}{4x-5}$$

Mā te whakawehe ki te 4x-5 ka wetekia te whakareanga ki te 4x-5.

$$y=-\frac{x^{2}}{4x-5}$$

Whakaoti mō x (complex solution)

$$x=\sqrt{y\left(4y+5\right)}-2y$$

$$x=-\sqrt{y\left(4y+5\right)}-2y$$

Whakaoti mō x

$$x=\sqrt{y\left(4y+5\right)}-2y$$

$$x=-\sqrt{y\left(4y+5\right)}-2y\text{, }y\leq -\frac{5}{4}\text{ or }y\geq 0$$