Whakaoti i te x^2+4=45

$$x ^ { 2 } + 4 = 45$$

Whakaoti mō x

$$x=\sqrt{41}\approx 6.403124237$$

$$x=-\sqrt{41}\approx -6.403124237$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 4 mai i ngā taha e rua.

$$x^{2}=45-4$$

Tangohia te 4 i te 45, ka 41.

$$x^{2}=41$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{41} x=-\sqrt{41}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 45 mai i ngā taha e rua.

$$x^{2}+4-45=0$$

Tangohia te 45 i te 4, ka -41.

$$x^{2}-41=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -41 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-41\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-41\right)}}{2}$$

Whakareatia -4 ki te -41.

$$x=\frac{0±\sqrt{164}}{2}$$

Tuhia te pūtakerua o te 164.

$$x=\frac{0±2\sqrt{41}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{41}}{2} ina he tāpiri te ±.

$$x=\sqrt{41}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{41}}{2} ina he tango te ±.

$$x=-\sqrt{41}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{41} x=-\sqrt{41}$$