Whakaoti i te x^2+4=-4

$$x ^ { 2 } + 4 = - 4$$

Whakaoti mō x (complex solution)

$$x=-2\sqrt{2}i\approx -0-2.828427125i$$

$$x=2\sqrt{2}i\approx 2.828427125i$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 4 mai i ngā taha e rua.

$$x^{2}=-4-4$$

Tangohia te 4 i te -4, ka -8.

$$x^{2}=-8$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{2}i x=-2\sqrt{2}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 4 ki ngā taha e rua.

$$x^{2}+4+4=0$$

Tāpirihia te 4 ki te 4, ka 8.

$$x^{2}+8=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 8 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 8}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 8}}{2}$$

Whakareatia -4 ki te 8.

$$x=\frac{0±\sqrt{-32}}{2}$$

Tuhia te pūtakerua o te -32.

$$x=\frac{0±4\sqrt{2}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{2}i}{2} ina he tāpiri te ±.

$$x=2\sqrt{2}i$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{2}i}{2} ina he tango te ±.

$$x=-2\sqrt{2}i$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{2}i x=-2\sqrt{2}i$$