Whakaoti i te x^2+3x=70

$$x ^ { 2 } + 3 x = 70$$

Whakaoti mō x

$$x=-10$$

$$x=7$$

Ngā Upane Whakamahi Tauwehe

Tangohia te 70 mai i ngā taha e rua.

$$x^{2}+3x-70=0$$

Hei whakaoti i te whārite, whakatauwehea te x^{2}+3x-70 mā te whakamahi i te tātai x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=3 ab=-70$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōrunga te a+b, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -70.

$$-1,70 -2,35 -5,14 -7,10$$

Tātaihia te tapeke mō ia takirua.

$$-1+70=69 -2+35=33 -5+14=9 -7+10=3$$

Ko te otinga te takirua ka hoatu i te tapeke 3.

$$a=-7 b=10$$

Me tuhi anō te kīanga whakatauwehe \left(x+a\right)\left(x+b\right) mā ngā uara i tātaihia.

$$\left(x-7\right)\left(x+10\right)$$

Hei kimi otinga whārite, me whakaoti te x-7=0 me te x+10=0.

$$x=7 x=-10$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Tangohia te 70 mai i ngā taha e rua.

$$x^{2}+3x-70=0$$

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei x^{2}+ax+bx-70. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=3 ab=1\left(-70\right)=-70$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōrunga te a+b, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -70.

$$-1,70 -2,35 -5,14 -7,10$$

Tātaihia te tapeke mō ia takirua.

$$-1+70=69 -2+35=33 -5+14=9 -7+10=3$$

Ko te otinga te takirua ka hoatu i te tapeke 3.

$$a=-7 b=10$$

Tuhia anō te x^{2}+3x-70 hei \left(x^{2}-7x\right)+\left(10x-70\right).

$$\left(x^{2}-7x\right)+\left(10x-70\right)$$

Tauwehea te x i te tuatahi me te 10 i te rōpū tuarua.

$$x\left(x-7\right)+10\left(x-7\right)$$

Whakatauwehea atu te kīanga pātahi x-7 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-7\right)\left(x+10\right)$$

Hei kimi otinga whārite, me whakaoti te x-7=0 me te x+10=0.

$$x=7 x=-10$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x^{2}+3x=70$$

Me tango 70 mai i ngā taha e rua o te whārite.

$$x^{2}+3x-70=70-70$$

Mā te tango i te 70 i a ia ake anō ka toe ko te 0.

$$x^{2}+3x-70=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 3 mō b, me -70 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-3±\sqrt{3^{2}-4\left(-70\right)}}{2}$$

Pūrua 3.

$$x=\frac{-3±\sqrt{9-4\left(-70\right)}}{2}$$

Whakareatia -4 ki te -70.

$$x=\frac{-3±\sqrt{9+280}}{2}$$

Tāpiri 9 ki te 280.

$$x=\frac{-3±\sqrt{289}}{2}$$

Tuhia te pūtakerua o te 289.

$$x=\frac{-3±17}{2}$$

Nā, me whakaoti te whārite x=\frac{-3±17}{2} ina he tāpiri te ±. Tāpiri -3 ki te 17.

$$x=\frac{14}{2}$$

Whakawehe 14 ki te 2.

$$x=7$$

Nā, me whakaoti te whārite x=\frac{-3±17}{2} ina he tango te ±. Tango 17 mai i -3.

$$x=-\frac{20}{2}$$

Whakawehe -20 ki te 2.

$$x=-10$$

Kua oti te whārite te whakatau.

$$x=7 x=-10$$

Ngā Upane mō te Whakaoti i te Pūrua

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$x^{2}+3x=70$$

Whakawehea te 3, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te \frac{3}{2}. Nā, tāpiria te pūrua o te \frac{3}{2} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}+3x+\left(\frac{3}{2}\right)^{2}=70+\left(\frac{3}{2}\right)^{2}$$

Pūruatia \frac{3}{2} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}+3x+\frac{9}{4}=70+\frac{9}{4}$$

Tāpiri 70 ki te \frac{9}{4}.

$$x^{2}+3x+\frac{9}{4}=\frac{289}{4}$$

Tauwehea x^{2}+3x+\frac{9}{4}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{3}{2}\right)^{2}=\frac{289}{4}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x+\frac{3}{2}\right)^{2}}=\sqrt{\frac{289}{4}}$$

Whakarūnātia.

$$x+\frac{3}{2}=\frac{17}{2} x+\frac{3}{2}=-\frac{17}{2}$$

Me tango \frac{3}{2} mai i ngā taha e rua o te whārite.

$$x=7 x=-10$$